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6a^2+18a-168=0
a = 6; b = 18; c = -168;
Δ = b2-4ac
Δ = 182-4·6·(-168)
Δ = 4356
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4356}=66$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-66}{2*6}=\frac{-84}{12} =-7 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+66}{2*6}=\frac{48}{12} =4 $
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